Acontractor combined x tons of a gravel mixture that contained 10 percent gravel g, by weight, with y tons of a mixture that contained 2 percent gravel g, by weight, to produce z tons of a mixture that was 5 percent gravel g, by weight. what is the value of x ?

The value of x would be or

Step-by-step explanation:

Given,

x tons of 10% gravel G mixture is mixed with y ton of 2% gravel G to obtain  5% gravel mixture,

Thus, gravel G in x ton + gravel in y ton = gravel G in the resultant mixture,          

⇒ 0.1x + 0.02y = 0.05(x+y),

0.1x - 0.05x = 0.05y - 0.02y

0.05x = 0.03y

Now, resultant mixture is z ton,

i.e.

From equation (1),

27 +27 or 27times 2=54

the diffrence is 0