Will brainlist answerer
the sum of three consecutive integers is
greater than or equal to -48. find the smallest
set of values that would make this true.

Th three consecutive integers are:

-17, - 16 , - 15

Step-by-step explanation:

Let the consecutive integers are:

x

x + 1

x + 2

According to given condition:

x + x + 1 + x + 2 = -48

Adding like terms

3x + 3 = -48

Subtracting 3 from both sides

3x = -48 - 3

3x = -51

Dividing by 3 on both sides

x = -51/3

x = - 17

So the three consecutive integers will be:

x = -17

x + 1 = -17 + 1 = -16

x + 2 = -17 + 2 = -15

I hope it will help you!

i believe the answer is c.