1. determine whether -3 is a root of x3 + 3x2 + x + 1 = 0.
explain.

2. write a polynomial equation of least degree with
roots 3,-1, 2i, and -2i. how many times does the
graph of the related function intersect the x-axis?

1. The given equation does not have root at x = - 3.

2. (x - 3) (x + 1) (x² + 4) = 0

This curve will intersect twice the x-axis.

Step-by-step explanation:

1. If the right hand side of the equation  ......... (1) becomes same as the left hand side by putting x = - 3, then only we can conclude that x = - 3 is a root of the equation.

But in this case .

Therefore, x = - 3 is not a root of the above equation (1).

2. The equation of the polynomial with roots 3, -1, 2i, and -2i is

(x - 3) (x + 1) (x - 2i) (x + 2i) = 0

⇒ (x - 3) (x + 1) (x² + 4) = 0 (Answer)

Therefore, the graph of the above curve will intersect twice the x-axis in a real coordinate plane, at x = 3 and at x = -1. (Answer)

answer

see attachment

explanation

the given function is

this function has y-intercept at

-4 and a slope of 2.

note that, the graph has a positive slope.

the graph that represents this function is the straight line that moves upward from left to right.

the graph touches the y-axis at -4.

the correct choice is the graph shown in the attachment.

answer: 140

step-by-step explanation:

so just add all then it will be your answer but i am not pretty sur eif it is but hope this i am here to people