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i have 3 questions for math

1. two lines have the given equations. use the linear combination method to solve.

2x-y=1

3x-y=-6

2. solve the system of equations using the substitution method

4x+2y = 10

y = 4x + 2

3. solve the system of equations using any method

6x – y = 2

y = 3x + 4

with work

May not be much help since I’m confused but if you want y or whatever, isolate the variable by doing the inverse operation.

For example if you add 2 subtract it so it will cancel out. Of course to balance the equation you must do it to te other side.

Ask yourself what is stopping the variable To be by itself?

And get rid of it bun doing the inverse operation

If you add, subtract

If you subtract, add

If you multiply, divide

If you divide, multiply

If your dealing with squared numbers, find the square root of it

If it’s sign isn’t there and it positive, subtract

If it’s sign isn’t there and it’s negative, add

Im sorry if i wasn’t much help!

2nd one in the first row is correct

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°