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i have 3 questions for math

1. two lines have the given equations. use the linear combination method to solve.

2x-y=1

3x-y=-6

2. solve the system of equations using the substitution method

4x+2y = 10

y = 4x + 2

3. solve the system of equations using any method

6x – y = 2

y = 3x + 4

with work

Step-by-step explanation:

1) 2x -y = 1 1

3x - y = -6 2

Subtract eqn 2 from eqn 1

-x = 1--6 = 7

x = -7

Put x= -7 in eqn 1

2*-7-y = 1

-14-y = 1

- y = 15

y = -15

2) 4x +2y = 101

y = 4x + 22

Put eqn 2 in eqn 1

4x + 2 ( 4x+ 2) = 10

4x + 8x + 4 = 10

12x = 6

x = 6/12 = 1/2

Put x = 1/2 in eqn 2

y = 4* 1/2 + 2= 2 + 2

= 4

3) 6x - y = 21

y = 3x + 42

Put eqn 2 in eqn 1

6x - (3x +4) = 2

6x - 3x - 4 = 2

3x = 6

x = 2

y = 3*2 + 4 = 6 + 4

= 10

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step-by-step explanation:

dont trust me im no expert these losers made me fail a test bro this sucks

step-by-step explanation: