Tickets for the community fair cost $12 for adults and $5 dollars for children. on the first day of the fair, 312 tickets were sold for a total of $2,204 . how many adult tickets and how many child tickets were sold?

With this information we can set up 2 equations:

x + y = 312      (# of tickets sold for adults + # of tickets sold to adults = 312)

12x + 5y = 2204 ( # of tickets sold for adults times $12 + # of tickets sold to adults times $5  = $2204)

Where x is how many  tickets were sold to adults and y how many tickets were sold to children

Now we can solve this system of equations by substitution:

isolate y in the first equation to find its value and plug it in the second equation

x + y = 312

isolate y by subtracting x from both sides:

x - x + y = 312

y = 312 - x

Apply y = 312 - x to the second equation

12x + 5y = 2204

12x + 5( 312 - x) = 2204

12x + 1560 - 5x = 2204

7x + 1560 = 2204

Subtract 1560 from both sides to isolate x

7x + 1560 - 1560 = 2204 - 1560

7x = 644

Divide both sides by 7

7/7x = 644/7

x = 92

Now plugin 92 for x in the first equation to find the value of y

x + y = 312

92 + y = 312

subtract 92 from both sides

92 - 92 + y = 312 - 92

y = 220

x = 92, y = 220

92 tickets were sold to adults and 220 tickets were sold to children

Hope it helps :)

Branliest would be appreciated

the camry sales+accord sale=828,000. to make it so the two numbers are 18 thousand apart and still equal 828,000, you first need to find out what half of 828,000 is. 828,000/2=414,000. for the two numbers to equal 828,000, you have to add the same amount as you subtract from the middle. in this case, the number is 9,000 because it's half of 18,000. to equal 828,000, you have to add 9,000 to 414,000 for the camry and subtract 9,000 from 414,000 for the accord. 414,000+9,000=423,000.

414,000-9,000=405,000.

423,000+405,000=828,000.

423,000-405,000=18,

hope it

for the free

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