The length of a rectangle is 4 cm longer than its width.
if the perimeter of the rectangle is 64 cm, find its length and width.

If the perimeter of the rectangle is 64 cm then the length is 18 cm and width is 14 cm

Solution:

Need to find the length and width of the rectangle.

Given that length of rectangle is 4 cm longer than it’s width

Let’s assume width of the rectangle = x cm

So length of the rectangle which is 4 cm longer that width = x + 4 cm.

Perimeter of rectangle = 2(length + width)       (1)

Also given that perimeter = 64 cm

Substituting given value of perimeter and assumed value of width and length in equation (1), we get

64 = 2 ((x + 4) + (x))

On solving above expression for x, we get  

64 = 2 (2x + 4)  

=> 64 = 4x + 8

=> 4x = 64 – 8 = 56

=>x = 14

Width of rectangle = x = 14 cm

Length of rectangle = x + 4 = 14 + 4 = 18 cm

Hence width of rectangle = 14 cm and length of rectangle = 18 cm.

false

step-by-step explanation:

4y - 6 + 4y^2 - 9

before simplifying this contains 4 terms

after simplifying

4y -15 + 4y^2

it contains 3 terms

b

step-by-step explanation: