Plane b is flying 55mph faster than plane a and can fly 4275 miles in the same amount of time it takes plane a to fly 4000 miles. find the amount of time it takes for each plane to travel their respective distances.

it takes 5s for each plane to travel their respective distances

Step-by-step explanation:

Let a = speed of plane A

Let b = speed of plane B

b = 55 + a

Time for plane A to fly 4000 miles

= 4000/a

Time for plane B to fly 4275 miles

= 4275/b

Since it takes same amount of time

4000/a = 4275/b

4000b = 4275a1

Put b = 55+a in eqn

4000(55+a) = 4275a

220000+4000a = 4275a

275a = 220000

a = 800

b = 55 +800 = 855

Time for plane A to fly 4000 miles

= 4000/800 = 5s

Time for plane B to fly 4275 miles

= 4275/855= 5s

$450.00 for 6 weeks

or

$300

step-by-step explanation:

$200.00 for first week $50.00 x5 equals $250 plus $200 equals $450.00 for six weeks.

$200 for first week

$200 x 0.10 = $20

$20 x 5 = $100

$200 + $100 = $300

use an equation of ratios to determine the amount of gas needed to fill the tank.

    0.2             0.8

  =    

288.75             x

                                                              231 gal

so, 0.2x = (0.8)(288.75 gal), and x = = 1155 gal.

                                                                0.2

it would take 1155 gal. to fill the tank.

the cost would be

1155 gal         $3

* = $3465   (answer)

      1           1 gal

hope this you