Solve the system of equations.
2x + 2y + 5z = 7
6x + 8y + 5z = 9
2x + 3y + 5z = 6
a. (x = 2, y = -1,2 - 1)
b. (x = 1, y = 0, z = 2)
c. (x = 3, y = -2, z = 0)
d. (x = 4, y = -3, z = 3)
select the best answer from the choices provided

using the first two equations cancelling the z

-2x-2y-5z=-7

6x+8y+5z=9

4x +6y= 2

using the second and the third equations cancelling the z

6x+8y+5z= 9

-2x-3y-5z= -6

4x +5y = 3

4x + 6y = 2

-4x -5y = -3

y= -1

2x + 2(-1) + 5z = 7

2x - 2 + 5z = 7

2x + 5z = 9

6x + 8(-1) + 5z = 9

6x - 8 + 5z = 9

6x + 5z = 17

-2x - 5z= -9

4x = 8

x = 2

2(2) + 2(-1) + 5z= 7

4 - 2 + 5z = 7

2 + 5z = 7

5z = 5

z = 1

(2, -1, 1)

the answer is a.

Step-by-step explanation:

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

what do u need to know

step-by-step explanation: