The ages of three siblings combined is 32 the oldest is three times the age of the youngest the middle child is three years younger than the oldest write and solve an equation to find the ages of each sibling

Age of oldest child = 15

Age of middle child = 12

Age of youngest child = 5

Step-by-step explanation:

let the age of youngest child be 'x';

now, according to the question;

age of oldest child = 3x

age of middle child = 3x - 3

also;

⇒ 32 = age of youngest child + age of middle child + age of oldest child

⇒ 32 = x + 3x - 3 + 3x

⇒ 7x = 35

⇒ x = 5

so,

age of youngest child = x = 5

age of middle child = 3x - 3 = 12

age of oldest child = 3x = 15

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

answer. d.289 hope that