There were a number of bats in a haunted house. two bats could see out of the right eye, three could see out of the left eye, four could not see out of the left eye and five could not see out of the right eye. what is the least number of bats in haunted house and what might their eyesight have been ( were they totally blind, blind only in the right eye, etc.?

18 units²

step-by-step explanation:

first let's find altitude bd using the distance formula

d = √((y₂ - y₁)² + (x₂ - x₁)²)

bd = √((0 - -3)² + (0 - 3)²)

bd = √18

given the placement of points a and c, we can denote that point d bisects segment ac.

we will call ac the base.

using the distance formula

ac = √((0 - 6)² + (-6 - 0)²)

ac = √72

knowing our base and our height, we can plug these into our triangle area formula

area = (b * h)/2

area = (√18 * √72) / 2

area = (√1296) / 2

area = 36 / 2

area = 18 units²

the answer is a. 72. but i cant answer with less than 20 characters so here's some random text talking about it.