Find the set of points that are part of a line that is perpendicular to the line y = ­-3x
a) (-3,-3), (3.-5)
b) (-6,-1), (3,2)
c) (-1, -1), (1, 5)
d) (3, -6), (-1, 6)

the answer is c. (-1, -1), (1, 5)

Step-by-step explanation:

perpindicular lines have reciprocal slopes.

reciprocal terms are two identical numbers, but with opposite signs.

the slope in y= -3x is -3, and the slope in (-1, -1), (1, 5) is 3.

b) (-6,-1), (3,2)

Step-by-step explanation:

We have an equation for a line that is:

where the number is the slope of the line, i will call this number , so

to be a perpendicular line, the slope of the new line must satisfy the following:

and since

so now we check which one of the options is part of a line with  a slope of 1/3, using the formula for the slope:

slope: , this set of points is NOT part of a perpendicular line.

slope:  this set of points are part of a perpendicular line because the slope of the line between them is which is the condition to be a perpendicular line.

i am currently in the exact same situation rn. algebra2/adv algebra is killing

step-by-step explanation:

hope this .

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