7. you are painting a large wall mural. the wall length is 3 times the height. the
area of the wall is 300 ft? .
a. what are the dimensions of the wall?
b. if each can of paint covers 22 ft? , will 12 cans be enough to cover the wall?

The wall length is 3 times the height.

The area of the wall is 300 sq. ft.

Height H = X

Length L = 3X

Area S = H x L = X x 3X = 300

3(X x X) = 300

X x X = 300/3 = 100

X = 10

a. What are the dimensions of the wall?

Height H = X = 10 ft

Length L = 3X = 30 ft

b. If each can of paint covers 22 sq. ft?, will 12 cans be enough to cover the wall?

12 cans will cover 22 x 12 = 264 sq. ft

The mural is 300 sq. ft.

So, 12 cans is not enough. You will need 14 cans.

18 units²

step-by-step explanation:

first let's find altitude bd using the distance formula

d = √((y₂ - y₁)² + (x₂ - x₁)²)

bd = √((0 - -3)² + (0 - 3)²)

bd = √18

given the placement of points a and c, we can denote that point d bisects segment ac.

we will call ac the base.

using the distance formula

ac = √((0 - 6)² + (-6 - 0)²)

ac = √72

knowing our base and our height, we can plug these into our triangle area formula

area = (b * h)/2

area = (√18 * √72) / 2

area = (√1296) / 2

area = 36 / 2

area = 18 units²