You are to drive to an interview in another town, at a distance of 270 km on an expressway. the interview is at 11: 15 a. m. you plan to drive at 100 km/h, so you leave at 8: 00 a. m. to allow some extra time. you drive at that speed for the first 110 km, but then construction work forces you to slow to 42.0 km/h for 43.0 km. what would be the least speed needed for the rest of the trip to arrive in time for the interview?

the least required speed  is 103.88 km/h

Step-by-step explanation:

Data provided in the question:

Total distance = 270 km

Total time to reach = Time between 8 a.m and 11:15 a.m i.e 3.25 hours

Now,

For the distance of 110 km speed was 100 km/h

therefore, the time taken to cover 110 km =

=

= 1.1 hour

For another 43 km speed was 42 km/h

therefore, the time taken to cover 43 km =  

=

= 1.0238 hours

Now,

The distance left to be covered = 270 - 110 - 43 = 117 km

Time left = 3.25 h - 1.1 h - 1.0238 h = 1.1262 h

Thus required speed =

= 103.88 km/h

Hence, the least required speed  is 103.88 km/h

answer:

(-8,7)

explanation:

we know that  

f

(

−

3

)

=

7

therefore, if we wish to get the output as 7, in the function, we need to have our input to be -3.

looking at the function  

f

(

x

+

5

)

, what should the value of x be, such that the input in the function becomes 7?

we simply equate the terms,

x

+

5

=

−

3

x

=

−

8

thus, the point on the new function would be  

(

−

8

,

7

)

50 min

step-by-step explanation:

they will be decreasing both their times in half

60 / 2 = 30

40/2 = 20

30 + 20 = 50