Beer shelf life is a problem for brewers and distributors because when beer is stored at room temperature, its flavor deteriorates. when the average furfuryl ether content reaches 6 μg per liter, a typical consumer begins to taste an unpleasant chemical flavor. at α = 0.05, would the following sample of 12 randomly chosen bottles stored for a month convince you that the mean furfuryl ether content exceeds the taste threshhold?
6.94 7.50 5.87 7.92 8.66 7.78 7.95 6.35 6.16 6.28 5.68 7.02
for the following hypothesis:
a) h0: μ ≤ 6 versus h1: μ > 6, what is the value of the test statistic?
b) what is the p-value?
c) at α = .05, we would
i. reject the null hypothesis.
ii. fail to reject the null hypothesis.

a) 3.52

b)  0.002399

c)  At α = .05 we reject the null hypothesis.

Step-by-step explanation:

We are given the following information:

Population mean, μ = 6 μg per liter

Sample size, n = 12

Alpha, α = 0.05

6.94, 7.50, 5.87, 7.92, 8.66, 7.78, 7.95, 6.35, 6.16, 6.28, 5.68, 7.02

where are data points, is the mean and n is the number of observations.

First, we design the null and the alternate hypothesis

We use One-tailed t test to perform this hypothesis.

a) Formula:

Putting all the values, we have

b) P-value for one tailed t-test at 11 degree of freedom and α = 0.05 is 0.002399

c) Since P-value < 0.05

The result is insignificant.

Thus, at α = .05 we reject the null hypothesis.

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v