An assembly line has two inspectors. the probability that the first inspector will miss a defective item is 0.06. if the defective item passes the first inspector, the probability that the second inspector will miss it is 0.07. what is the probability that a defective item will pass by both inspectors?

probability that both passes a defective item is  0.8742‬

probability that the first inspector misses is Pr( 1st misses)= 0.06

therefore the probability he does not miss is

Pr(1st passes)= 1 - Pr( 1st misses) = 1 - 0.06 = 0.94

probability that the second misses is Pr( 2nd misses) = 0.07

therefore probability that 2nd does not miss is

Pr( 2nd passes) = 1- Pr( 2nd misses) = 0.93

probability that both passes a defective item is  Pr(1st passes)*Pr( 2nd passes)

= 0.93*0.94 = 0.8742‬

idk

step-by-step explanation:

students group

step-by-step explanation:

a person who   joins a party or a seminar can explain his feelings about that particular occasion better more than anyone else.

as bella managed a show for the students in the school and invited students to watch that show

hence

students group will be the best group to survey to find this information