In a group of 92 students 40 have brown eyes, 35 have hazel eyes, and 17 have blue eyes. find the probability that a student picked from this group at random either has hazel or brown eyes? enter your answer as a fraction in the form a/b (for example 2/3, 5/7) or as an integer.

as a fraction = 75/92

as a percentage = 81.52%

Step-by-step explanation:

total no of students = 92

probability that a student has hazel or brown eyes = Pr(hazel or brown)

but probability of a or b happening ie Pr(a or b) simply is Pr (a) +Pr (b)

therefore Pr(hazel or brown) = Pr(hazel)+ Pr(brown)

Pr(brown) = (no of brown eyes )/(total set of eyes)

                = = 10/23

Pr( hazel) = (no of hazel eyes )/(total set of eyes)

                  = =35/92

hence Pr(hazel or brown) = (10/23) + (35/92) =75/92

so there's 75/92 probability (or 0.8 out of 1 chance )to choose either hazel or brown randomly

3. parallelogram

step-by-step explanation:

we turn each of our sides into direction vectors

ab=b-a=(3 - 7, 1 - 0) = (-4, 1)

bc=c-b=(1,6)

cd=d-c=(4,-1)

da=a-d=(-1,-6)

we see how the opposite sides have negated direction vectors; this is characteristic of a parallelogram.   we have congruent sides ab=cd and bc=da with unequal lengths because 1^2+6^2 is different from (-4)^2+1^2.   so it's not a square or a rhombus.  

we check the dot product of direction vectors of adjacent sides.   we have

ab dot bc = -4(1) + 1(6) = 2

that's not zero so the sides are not perpendicular.   we've ruled out rectangle.

the direction vectors indicate two pairs of congruent parallel sides, so we choose parallelogram over trapezoid.

4x and 6y

im not sure though