What is the completely factored form of d^4 - 81

Step-by-step explanation:

d^4-81

(d^2)^2-(9)^2

Using formula

(d^2+9)(d^2-9)

(d - 3)(d + 3)(d² + 9)

Step-by-step explanation:

- 81 ← can be factored as a difference of squares

a² - b² = (a - b)(a + b), thus

- 81

= (d²)² - 9²

= (d² - 9)(d² + 9)

Note that d² - 9 is also a difference of square, so

= (d - 3)(d + 3)(d² + 9) ← in factored form

where r the answers

step-by-step explanation:

he kicked it up? is this the answer ?

step-by-step explanation: