Atheatre sold a total of 780 adult and student tickets. an adult ticket costs $8, a student ticket costs $3, and the total ticket sales were $4,440. write a system of equations and find the number of adult and student tickets sold.

Number of Adult tickets sold = 420

Number of Students tickets sold = 360

Step-by-step explanation:

Given as ,

Number of adult ticket + Number of Students tickets = 780  

Each Adult ticket cost = $8

Each Student ticket cost = $3

Total of ( Adult ticket cost + Student ticket cost) = $ 4,440

i.e

A + S = 780         1

And 8A + 3S = 4440         2

Solve eq 1 and 2

Or, 8A + 3S = 4440

     3A + 3S = 2340

Or, (8A + 3S) - (3A + 3S) = (4440 - 2340)

or,  5A = 2100

So, A = 420    

Now put this A value in eq 1

So 420 + S = 780

Or, S = 780 - 420

So , S = 360  

Hence The Number of Adult tickets sold = 420

And     The Number of Student tickets sold = 360

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

stop cheating

step-by-step explanation: