If we know that the length of time it takes a college student to find a parking spot in the library parking lot follows a normal distribution with a mean of 3.5 minutes and a standard deviation of 1 minute, find the probability that a randomly selected college student will take between 2 and 4.5 minutes to find a parking spot in the library parking lot, rounding to four decimal places.

0.7745

Step-by-step explanation:

Given :  The length of time it takes a college student to find a parking spot in the library parking lot follows a normal distribution with minutes and minute.

Let x represents the time to find a parking spot in the library parking lot.

Since ,

z-score corresponds x = 2 ,

z-score corresponds x = 4.5 ,

Required probability :

[using z-value table.]

Hence, the  probability that a randomly selected college student will take between 2 and 4.5 minutes to find a parking spot in the library parking lot, (rounding to four decimal place )= 0.7745

f(x) = y

f(-3) = -5

step-by-step explanation: