Arsenic is a compound that occurs naturally in very low concentrations. arsenic blood concentrations in healthy adults are normally distributed, with mean =3.2μ=3.2 micrograms per deciliter /dl)(μg/dl) and standard deviation =1.5 /dlσ=1.5 μg/dl . what is the range of arsenic blood concentrations corresponding to the middle 90% of healthy adults?

range of arsenic blood concentrations: 0.725 μg/dl  - 5.675 μg/dl

Step-by-step explanation:

Data

μ=3.2 μg/dl

σ=1.5 μg/dl

Let's call x1 the maximum arsenic blood concentrations and x2 the minimum concentration for the range corresponding to the middle 90% of healthy adults. To get x1 is necessary to find the x for that the area below the standard normal distribution is 0.45. In table attached it can be seen that this area correspond to Z = 1.65. Using Z definition, x1 can be isolated

Z = (x1-μ)/σ = 1.65

x1 = 1.65*σ + μ

x1 = 1.65*1.5 + 3.2

x1 = 5.675 μg/dl

Knowing that normal distribution is symmetrical respect to 0, then the area between Z = -1.65 and Z = 0 is also 0.45. So, x2 is computed as

Z = (x2-μ)/σ = -1.65

x2 = -1.65*σ + μ

x2 = -1.65*1.5 + 3.2

x2 = 0.725 μg/dl

a

step-by-step explanation:

1. x> -5

2. x< 8

step-by-step explanation:

1. 2x> -10

divide by 2 from both sides of equation.

2x/2> -10/2

simplify, to find the answer.

-10/2=-5

x> -5 is the correct answer.

2. 3x< 24

divide by 3 from both sides of equation.

3x/3< 24/3

simplify, to find the answer.

24/3=8

x< 8 is the correct answer.

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