The back of george's property is a creek. george would like to enclose a rectangular area, using the creek as one side and fencing for the other three sides, to create a pasture. if there is 140 feet of fencing available, what is the maximum possible area of the pasture?

The maximum possible area of the pasture = 2450 square feet

Step-by-step explanation:

Let the length of the creek be 'L'

and, the width of the rectangular area be 'B'

Data provided:

The rectangular area is enclosed using the creek as one side and fencing for the other three sides

Thus, 2B + L = 140 feet      

or

L = 140 - 2B              .........(1)

Now,

Area of the rectangular land, A = L × B

using (1)

A = ( 140 - 2B) × B

or

A = 140B - 2B²

Now to maximize the area, differentiating the area with respect to width 'B'

we have

 = 140 - 2 × 2 × B ...........(2)

for point of maxima or minima ,  = 0

thus,

140 - 2 × 2 × B = 0

or

4B = 140

or

B = 35 feet

differentiating  (2) with respect to B, for verifying the maxima or minima

 = 0 - 2 × 2 = -4

since, is negative,

therefore,

B = 35 feet is point of maxima

from (1)

L = 140 - 2B

or

L = 140 - 2 × 35

or

L = 140 - 70 = 70 feet

Hence,

The maximum possible area of the pasture = L × B

= 70 × 35

= 2450 square feet

i think the answer is d im not sure

a.) list the factors of 40.

1/2/4/5/8/10/20/40

b.) list the factors of 40 that represent the number of cans that could be on each shelf.

5

c.) how many different arrangements of cans are possible?

just one because if you put more on one shelf you will go way over 40 and the cabinet will probably break.

d.) what are the possible arrangements of the cans?

put 5 cans on each self to reach 40 cans in total.

e.) which arrangement uses all the shelves?

5 because you can put 5 cans on each shelf, and since there are 8 shelfs you are equally going to get 40 cans.