Shelly rode her mountain bike at a rate of 30 km/h for 2.5 h. josh rode his mountain bike at a rate of 35 km/h for 1 h and then slowed down to 25 km/h for 1.5 h. a) who travelled farther in 2.5 h? b) what is the difference in the distance travelled by the cyclists?

Part A) Shelly traveled farther in 2.5 h

Part B) The difference in the distance traveled by the cyclists is 2.5 kilometers

Step-by-step explanation:

Part A) Who traveled farther in 2.5 h?

we know that

The speed is equal to divide the distance by the time

Let

s ----> the speed

d ----> the distance in kilometers

t ----> the time in hours

Solve for d

step 1

Find out the distance traveled by Shelly

we have

substitute the values

step 2

Find out the distance traveled by Josh

we have

Part 1)

substitute the values

Part 2)

substitute the values

substitute

Compare the distances

so

Shelly traveled farther in 2.5 h

Part B) What is the difference in the distance traveled by the cyclists?

Find out the difference between the two distances

10a^3+277a^2-132a-792

step-by-step explanation:

(2a+11)(5a-12)(foil)

=10a^2-24a+55a-132 =10a^2+31a-132

(10a^2+31a-132)(a+6)

=10a^3+60a^2+31a^2+186a^2-132a-792 =10a^3+277a^2-132a-792

i hope this is what you are looking for : )

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step-by-step explanation: