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look at the figure shown below:

rq is a segment on which a perpendicular bisector ps is drawn. s is the midpoint of rq.

which step should be used to prove that point p is equidistant from points r and q? (1 point)

a if any one side and any one common angle are congruent in triangles pqr and prs, then their corresponding sides are also congruent.

b. if two sides and one included angle are congruent in triangles pqs and prs, then their third sides are congruent.

c. in triangles pqr and pqs, if one side and one angle are congruent, then their corresponding sides and angles are also congruent.

d. in triangles prs and pqs, all three angles are congruent.

These are the steps, with their explanations and conclusions:

1) Draw two triangles: ΔRSP and ΔQSP.

2) Since PS is perpendicular to the segment RQ, ∠ RSP and ∠ QSP are equal to 90° (congruent).

3) Since S is the midpoint of the segment RQ, the two segments RS and SQ are congruent.

4) The segment SP is common to both ΔRSP and Δ QSP.

5) You have shown that the two triangles have two pair of equal sides and their angles included also equal, which is the postulate SAS: triangles are congruent if any pair of corresponding sides and their included angles are equal in both triangles.

Then, now you conclude that, since the two triangles are congruent, every pair of corresponding sides are congruent, and so the segments RP and PQ are congruent, which means that the distance from P to R is the same distance from P to Q, i.e. P is equidistant from points R and Q

sing SAS postulate, prove that triangles PQS and PRS are congruent.

you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)