In a certain city, 30% of the families have a mastercard, 20% have an american express card, and 25% have a visa card. eight percent of the families have both a mastercard and an american express card. twelve percent have both a visa card and a mastercard. six percent have both an american express card and a visa card. what is the probability of selecting a family that has either a visa card or an american express card?

Step-by-step explanation:

To solve this problem, we must build the Venn's Diagram of these probabilities.

I am going to say that:

-The set A represents the probability that a family has a MasterCard.

-The set B represents the probability that a family has an American Express Card.

-The set C represents the probability that a family has a Visa card.

We have that

In which a represents the probability that the family only has a MasterCard, represents the probability that the family has both a MasterCard and an American Express card and represents the probability that the family has both a Master and a Visa card.

By the same logic, we also have that:

What is the probability of selecting a family that has either a Visa card or an American Express card?

This is .

We start finding the probabilities from the intersection of these sets.

Six percent have both an American Express card and a Visa card. This means that:

Twelve percent have both a Visa card and a MasterCard

Eight percent of the families have both a MasterCard and an American Express card.

25% have a Visa card

20% have an American Express card

What is the probability of selecting a family that has either a Visa card or an American Express card?

There is a 13% probability of selecting a family that has either a Visa card or an American Express card

don't know sorry bru

step-by-step explanation:

b

step-by-step explanation:

the word superfluous means unnecessary