G(x)=27x^3+125
find factors of the binomial g(x).

a. g(x)= (3x+5)(9x^2+15x+25)

b. g(x)= (3x-5)(9x^2+15x+25)

c. g(x)= (3x+5) (9x^2-15x+25)

d. g(x)= (3x-5)(9x^2-15x+25)

The answer to your question is: (3x + 5)(9x² - 15x + 25)

Step-by-step explanation:

Data

G(x) = 27x³ + 125

This is a sum of cubes

Process

      27x³ + 125 = (3x)³ + (5)³ = (3x + 5)(9x² - 15x + 25)

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b