Two rectangles or similar one is 5 cm x 12 cm the long side of the second rectangle is 8 cm greater than twice is short side find its length and width

The length is 48

The width is 20

Step-by-step explanation:

When 2 rectangles (figures) are similar, the ratio of corresponding sides are equal.

This rectangle is 5 by 12, so the shorter side (corresponding to 5) to the longer side (corresponding to 12) would be the same ratio, 5:12.

Let shorter side be s, and

longer side be l

It says, long side is 8 greater than twice short, we can write this as:

In similar rectangles, we have said the corresponding sides' ratio are equal, so we could write:

Now, we replace the new found expression for "l" onto this and cross multiply and solve for s first:

So the shorter side is 20. and hence the longer side would be:

l = 2s + 8

l = 2(20) + 8

l = 40 + 8

l = 48

The longer side is 48.

The length is 48

The width is 20

d. bc = 12 and ef = 16

step-by-step explanation:

we are given that δabc : δdef such that .

also, it is given that

so, from the options, we need that .

a.

b.

c.  

d.

as, we can see that only option d gives the same ratio as i.e. .

hence, the possible lengths are bc = 12 and ef = 16.

46.2+112.3

step-by-step explanation: