Given the equation square root of quantity 3x minus 2 end quantity equals 4, solve for x and identify if it is an extraneous solution.

Step-by-step explanation:

This is your equation:

To undo that square root, square both sides, giving you:

3x - 2 = 16.  Solving for x gives us

3x = 18 so

x = 6

If you plug 6 back into the equation, the original one, you get that the square root of 16 = 4, which is true.

- 2 + 10x³ - 21x² + 19x - 4

step-by-step explanation:

each term in the second factor is multiplied by each term in the first factor

x²(- 2x² + 4x - 1) - 3x(- 2x² + 4x - 1) + 4(- 2x² + 4x - 1) ← distribute

= - 2 + 4x³ - x² + 6x³ - 12x² + 3x -8x² + 16x - 4

collect like terms

= - 2 + 10x³ - 21x² + 19x - 4 ← in standard form