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![\bf n^{th}\textit{ term of an arithmetic sequence} \\\\ a_n=a_1+(n-1)d\qquad \begin{cases} a_n=n^{th}\ term\\ n=\textit{term position}\\ a_1=\textit{first term}\\ d=\textit{common difference}\\[-0.5em] \hrulefill\\ n= 10\\ a_1=1531\\ d=76 \end{cases} \\\\\\ a_{10}=1531+(10-1)76\implies a_{10}=1531+(9)76\implies a_{10}=1531+684 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill a_{10}=2215~\hfill](/tpl/images/0348/7967/69dcc.png)
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Find the 10th term if a1=1531 and d=76....
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