Evaluate 6t -20-32u6t−20−32u6, t, minus, 20, minus, 32, u when t=6t=6t, equals, 6 and u=\dfrac14u=
4
1

u, equals, start fraction, 1, divided by, 4, end fraction.

The question is:

Evaluate 6t−20−32u when t=6 and u=1/4

8

Step-by-step explanation:

The given expression is:

We need to evaluate the expression for the given values of t and u. Substituting t=6 and u=1/4 in the above expression we get:

Thus, the give expression is equal to 8 for t=6 and u=1/4