Gis the incenter, or point of concurrency, of the angle bisectors of δace.

triangle a c e has point g as its incenter. lines are drawn from the points of the triangle to point g. lines are drawn from point g to the sides of the triangle to form right angles. line segments g b, g d, and g f are formed. angle f e g is (3 n minus 1) degrees and angle d e g is 20 degrees.
what is the value of n?

6
7
20
59

  7

Step-by-step explanation:

The two angles of interest are either side of angle bisector EG, so are congruent.

  3n -1 = 20

  3n = 21 . . . . . add 1

  n = 7 . . . . . . . divide by 3

im alright what do you need

step-by-step explanation:

yes

step-by-step explanation:

so of course you want to start by plugging the 5 in which goes to 7(5)+3(5)=50 because 7*5=35 and 3*5=15 and then add them together, then plug in the 5 to the other equation as well 9(5)+5=50 because 9*5= 45 and then add 5 and so yes they are equivalent.