Acompany produces 3 types of widgets. on a given day, the company was able to produce 9 total widgets (combining all 3 types). widget a costs $3 to produce, widget b costs #2 to produce, and widget c costs $1 to produce. the cost to produce the widgets each day is $18. the company produces one more widget b than the sum of the widgets a & c. how many of each type of widget is produced?

Number of widgets A and C are 2 each, widgets B are 5.

Step-by-step explanation:

Let be the number of widgets A, be the number of widgets B and be the number of widgets C.

As per the question,

On a given day, total 9 widgets are produced. So,

Cost for 1 widget A is $3. So, cost of widgets A is 3x.

Cost for 1 widget B is $2. So, cost of widgets A is 2y.

Cost for 1 widget C is $1. So, cost of widgets A is z.

Now, total cost of the widgets is $18. So,

Also, widget B is one more than the sum of widgets A and C. So,

Now, we have 3 equations and 3 unknowns.

⇒

Now, using the first and third equation, we get

Plug in 5 for in the first 2 equations. This gives,

⇒

⇒

Subtracting the above 2 equations, we get,

Using the value of x in the above equation, we find z.

Therefore,

Hence, number of widgets A and C are 2 each, widgets B are 5.

walter needs to make at least 5 more cookies but no more than 40. 5 ≤ x ≤ 40

step-by-step explanation:

20 ≤ x + 15 ≤ 55

subtract 15 from all parts

20-15 ≤ x + 15-15 ≤ 55-15

5 ≤ x ≤ 40

this means how many more cookies he has to make

walter needs to make at least 5 more cookies, but no more than 40 cookies; 5 ≤ x ≤ 40