Suppose that an accounting firm does a study to determine the time needed to complete one person's tax forms. it randomly surveys 175 people. the sample average is 23.3 hours. there is a known population standard deviation of 6.2 hours. the population distribution is assumed to be normal. note: if you are using a student's t-distribution, you may assume that the underlying population is normally distributed. (in general, you must first prove that assumption, though.) construct a 90% confidence interval for the population average time to complete the tax forms

(22.53, 24.07)

Step-by-step explanation:

As per given we have,

n= 175 ,  ,

Critical value for 90% confidence interval :

The population distribution is assumed to be normal.

Since population standard deviation is known , so we use z-test.

Confidence interval :

Hence,  a 90% confidence interval for the population average time to complete the tax forms = (22.53, 24.07)

after simplifying it i got: -36.25 as my answer. hope that !

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet