The composer beethoven wrote 9 symphonies, 5 piano concertos (music for piano and orchestra), and 32 piano sonatas (music for solo piano). (a) how many ways are there to play first a beethoven symphony and then a beethoven piano concerto? (b) the manager of a radio station decides that on each successive evening (7 days per week), a beethoven piano sonata will be played followed by a beethoven symphony followed by a beethoven piano concerto. for how many years could this policy be continued before exactly the same program would have to be repeated? (assume there are 365 days in a year. round your answer up to the nearest whole number.)

a. 45ways b.3.95years

Step-by-step explanation:

The composer Beethoven wrote 9 symphonies, 5 piano concertos, and 32 piano sonatas

(a) There are 9*5 ways to play first a Beethoven symphony and then a Beethoven piano concerto

9*5=45

(b) The manager of a radio station decides that on each successive evening (7 days per week), a Beethoven piano sonata will be played followed by a Beethoven symphony followed by a Beethoven piano concerto.

there are 32*9*5 combinatios of piano sonata followed by a Beethoven symphony followed by a Beethoven piano concerto.

32*9*5=1440

1440 nights / 365 days= 3.95 years

439400

step-by-step explanation:

130^2 = 16900

16900*26 = 439400

correct answer is infinitely many solutions

step-by-step explanation:

2(2x + 3) = -4 + 2(2x + 5)

solving the above equation:

4x + 6 = -4 +4x +10

combining like terms

4x -4x = -4+10-6

0=0

since both sides are 0=0, we end up into true statement it means it has infinite many solutions.

so correct answer is infinitely many solutions