Nonpoint source loads are chemical masses that travel to the main stem of a river and its tributaries in flows that are distributed over relatively long stream reaches, in contrast to those that enter at well-defined and regulated points. an article suggests that for a certain time period and location, x = nonpoint source load of total dissolved solids could be modeled with a lognormal distribution having mean value 10,827 kg/day/km and a coefficient of variation cv = 0.40 cv = σx μx .what are the mean value and standard deviation of ln(x)?

Mean 9.2898

Standard deviation 0.006

Step-by-step explanation:

Let m and s the mean and standard deviation of the non-logarithmized  

distribution and ,  the mean and standard deviation of the logarithmized one.

m = 10,827

Since the CV=0.4, then

s/m=0.4 and  

s = 10,827*0.4 = 4,330.8

The mean of the logarithmized distribution is

and the standard deviation is

this linear equation would have just one solution.

step-by-step explanation:

the reason why this would have one solution is that it is an expression with just one variable. since that variable is not raised to a power, it will always have just one solution.

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step-by-step explanation: