Aline segment has endpoints j (2,4) and l (6,8). the point k is the midpoint of jl. what is an equation of a line perpendicular of jl and pass through k?

a. y=- x +10
b. y=- x - 10
c. y= x + 2
d. y= x- 2

(- 1, 0 )

step-by-step explanation:

an x- intercept is where the function crosses the x- axis.

to find the x- intercept/s look for the value of x when f(x) = 0

from the given table there are 3 values of x where f(x) = 0

when x = - 1, x = 2, x = 3

the one that is listed is (- 1, 0 )

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