Find the value of a if f(x)—> a(x-1)(x+2) contains the points (-2,0) (1,0) and (3,5).

The value of a is 0.5

Step-by-step explanation:

we have

we know that

If a ordered pair lie on the graph of the function, then the ordered pair must satisfy the function

substitute the coordinates of point (3,5) in the function above and solve for a

For x=3, f(x)=5

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)

its an acute right triangle

step-by-step explanation: