At your school, 20% of the class are marketing majors. you are randomly assigned to two partners in your statistics class. a) what is the probability that the first partner will be a marketing major? b) what is the probability that the first partner won't be a marketing major? c) what is the probability that both will be marketing majors? d) what is the probability that at least one will be a marketing major?

a) 20%

b) 80%

c) There is 4% probability that both will be marketing majors.

d) There is a 36% probability that at least one will be a marketing major.

Step-by-step explanation:

At your school, 20% of the class are marketing majors.

This means that for each student, there is a 20% that he is a marketing major and an 80% chance that he is not a marketing major.

a) What is the probability that the first partner will be a marketing major?

The probabilities for each student are independent, so it is 20%.

b) What is the probability that the first partner won't be a marketing major?

80%

c) What is the probability that both will be marketing majors?

For each one, it is 20%. So:

There is 4% probability that both will be marketing majors.

d) What is the probability that at least one will be a marketing major?

That is one of them or both. For both, we found in c) that it is 4%.

For one of them, there are two cases. Either the first partner is and the second is not, or the other way. So, the probability that at least one will be a marketing major is

There is a 36% probability that at least one will be a marketing major.

it's d.

step-by-step explanation:

because: -1(4x + 1y) +2 (1x-3y) distribute each number into the parenthesis.

then you would get: -4x - 1y + 2x -6y combine like terms

and get: 2x -7y

hope my answer has you if not then i'm sorry.