Rectangle jklm: j(-3, 8), k(-3,-1), l(4, -1),
m(4,8)
jk = 8 +1 -1=
kl=1-3+4 =
perimeter units?

- 70

this is the answer for you hope it

2 over 5 and 4 over 15

don’t know last one sorry

step-by-step explanation:

correct choice is a

step-by-step explanation:

the equation of the line passing through the points and is

thus, the equation of the line that passes through the points (0, -6) and (-3, 0) is

no oblique asymptote

step-by-step explanation:

to find the oblique asymptote of f(x)

here numerator has degree 1 and denomintor degree 2

degree of numerator < degree of denominator

hence there is no oblique asymptote

when the degree of the denominator > that of the numerator, we saw that the value in the denominator got so much bigger, so quickly,   giving us a horizontal asymptote of the x-axis. or we can write

f(x) = a polynomial of x + a proper fraction.

in this case only we have oblique asymptotes but not when numerator has less degree.