The table shows a proportional relationship between the mass, in kilograms
(
kg
)
(kg)left parenthesis, start text, k, g, end text, right parenthesis, of a dog and the milliliters
(
ml
)
(ml)left parenthesis, start text, m, l, end text, right parenthesis of flea medicine a veterinarian prescribes.
flea medicine prescriptions
dog's mass
(
kg
)
(kg)left parenthesis, start text, k, g, end text, right parenthesis medicine
(
ml
)
(ml)left parenthesis, start text, m, l, end text, right parenthesis
50
5050
2
22
10
1010
0.4
0.40, point, 4
5
55
0.2
0.20, point, 2
? ?
a row of values is missing in the table.
which of the following numbers of kilograms and milliliters could be used as the missing values in the table?
choose 2 answers:
choose 2 answers:

(choice a)
a
dog:
15
 
kg
15kg15, start text, k, g, end text
medicine:
0.9
 
ml
0.9ml0, point, 9, start text, m, l, end text

(choice b)
b
dog:
25
 
kg
25kg25, start text, k, g, end text
medicine:
0.8
 
ml
0.8ml0, point, 8, start text, m, l, end text

(choice c)
c
dog:
40
 
kg
40kg40, start text, k, g, end text
medicine:
1.6
 
ml
1.6ml1, point, 6, start text, m, l, end text

(choice d)
d
dog:
35
 
kg
35kg35, start text, k, g, end text
medicine:
1.4
 
ml
1.4ml1, point, 4, start text, m, l, end text

(choice e)
e
dog:
20
 
kg
20kg20, start text, k, g, end text
medicine:
1.2
 
ml
1.2ml1, point, 2, start text, m, l, end text

C) Dog: 40 kg, Medicine: 1.6 mL

D) Dog: 35 kg, Medicine: 1.4 mL

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form or

Let

x --->  the mass, in kilograms of a dog

y ---> milliliters of flea medicine a veterinarian prescribes

Find the value of the constant of proportionality k for the given data

For x=50 kg, y=2 mL ---->

For x=10 kg, y=0.4 mL ---->

For x=5 kg, y=0.2 mL ---->

so

The linear direct equation is equal to

Verify each choice

A) Dog: 15 kg, Medicine: 0.9 mL

Divide the milliliters of medicine by the kilograms of the dog and compare the result with the constant of proportionality

so

therefore

These numbers could not be used as the missing values in the table

B) Dog: 25 kg, Medicine: 0.8 mL

Divide the milliliters of medicine by the kilograms of the dog and compare the result with the constant of proportionality

so

therefore

These numbers could not be used as the missing values in the table

C) Dog: 40 kg, Medicine: 1.6 mL

Divide the milliliters of medicine by the kilograms of the dog and compare the result with the constant of proportionality

so

therefore

These numbers could  be used as the missing values in the table

D) Dog: 35 kg, Medicine: 1.4 mL

Divide the milliliters of medicine by the kilograms of the dog and compare the result with the constant of proportionality

so

therefore

These numbers could be used as the missing values in the table

E) Dog: 20 kg, Medicine: 1.2 mL

Divide the milliliters of medicine by the kilograms of the dog and compare the result with the constant of proportionality

so

therefore

These numbers could not be used as the missing values in the table

Dog: 40 kg

Medicine: 1.6mL

Dog: 35 kg

Medicine: 1.4mL

Step-by-step explanation:

This combination has 0.040.040, point, 04 milliliters of medicine per kilogram of the dog's mass, which is the same as in the table.  

This combination has 0.040.040, point, 04 milliliters of medicine per kilogram of the dog's mass, which is the same as in the table.

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step-by-step explanation:

the answer is d

step-by-step explanation: