Given that z is a standard normal random variable, find z for each situation (to 2 decimals).

a. the area to the left of z is .9738

b. the area between 0 and z is .4738 ( is positive).

c. the area to the left of z is .8531

d. the area to the right of z is .1251

e. the area to the left of z is .6700

f. the area to the right of z is .3300

sinn is the total amount of students now and m were the students before, you subtract them both (n-m) and divide that by m. then, since to get a percentage from a fraction you have to multiply by 100, your answer should look like this: n-m/m*100

step-by-step explanation:

75%

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explanation:

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