Two sisters have ages that are consecutive, odd integers. when the younger one doubles her age and the older one triples her age, the sum of the results is 121. what are their ages?

Age of two sisters are 23 and 25.

Solution:

Given that two sisters have ages that are consecutive odd integer.

Let age of younger sister be x.

So age of older sister will be x + 2, as there is a difference of two in consecutive odd integers.

On doubling age of younger sister we get =

On tripling age of older one we get 3 (x + 2)  = 3x + 6

Also given that sum of double age of younger one and triple age of older one = 121

=> (2x) + (3x + 6) =121

=> 5x + 6 = 121

=> 5x = 121 – 6 = 115

=> x = 23

Age of younger sister = x = 23.

Age of older sister = (x + 2) = 23 + 2 = 25

Hence age of two sisters are 23 and 25.

-60.75

step-by-step explanation:

just add the numbers then put the negative sign on it