Roland has 3 paperback books and 4 hardcover books. each hardcover book is worth $11 more than each paperback book. if the value of all of his books is $79, what is the cost of one paperback book?

$5

Step-by-step explanation:

Let cost of paperback book be "p"

and

Cost of hardcover book be "h"

Each hardcover is $11 more than each paperback, thus we can write:

h = p + 11

3 paperbacks at "p" each and 4 hardcovers at "h" each totals 79, thus we can write:

3p + 4h = 79

We can now put the 1st equation in 2nd equation and find "p" (cost of paperback book). Shown below:

Hence, each paperback book costs $5

answer: option a.

step-by-step explanation:

you know that the quadrilateral opqr ( a four sided figure) is inscribed in circle. this means that all its vertices are on the circle.

then, by definition, the opposite angles of the quadrilateral are supplementary, this means that the sum of their measures is 180 degrees.

you can observe in the figure that the angles ∠opq   and the angle ∠orq   are opposite, therefore:

then, can be used to d to calculate the measure of ∠opq