Amarketing consultant observed 40 consecutive shoppers to estimate the average money spent by shoppers in a supermarket store. assume that the money spent by the population of shoppers follow a normal distribution with a standard deviation of $21.51. what is the probability that the average money spent by a sample of 40 shoppers is within $10 of the actual population mean. 0.1389

P (average within 10) = 0.9984

Step-by-step explanation:

Given:

Number of consecutive shoppers observed, n = 40

Standard deviation, σ = $21.51

Now,

Standard error (SE) =

or

Standard error (SE) =

or

Standard error (SE) = 3.40

also,

z =

on substituting the values, we have

z =

or

z = 2.94

Now, from the Table of Area Under Standard Noral Curve

for z = 2.94 ; area = 0.9984

we have P (average within 10) = 0.9984

spinning a 1, 2, or 3. option d.

step-by-step explanation: when spinning a number graph up to 4, and aiming for any number less than 3, that automatically eliminates the number 4. now you have two numbers to spin on that are less than 3, but the number 3 is included in this question because it's no greater of an number than itself. i hope this you : )