What is the vertex, axis of symmetry, and the direction of opening for y=2(x+3)^2-5

Its vertex is (-3 , -5)

Its axis of symmetry is at x = -3

The direction of opening of it is upward

Step-by-step explanation:

The vertex form of the quadratic function is:

y = a(x - h)² + k, where

1. The coordinates of its vertex point are (h , k)

2. Its axis of symmetry is at x = h

3. The direction of opening is upward if a > 0, and downward if a < 0

∵ y = 2(x + 3)² - 5

∵ y = a(x - h)² + k

∴ a = 2 , h = -3 and k = -5

∵ The coordinates of the vertex are (h , k)

∴ The vertex is (-3 , -5)

∵ The axis of symmetry is ta x = h

∴ The axis of symmetry is at x = -3

∵ a = 2 and 2 > 0

∴ The direction of opening is upward

Its vertex is (-3 , -5)

Its axis of symmetry is at x = -3

The direction of opening of it is upward

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find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation:

55 degrees because 55+55=110 degrees