Radius of circle o has a slope of 2.5. what is the slope of the line tangent to circle o at point a?
a.
0.8
b.
2.5
c.
-0.4
d.
-5

- 0.4

Step-by-step explanation:

The radius of a circle and a tangent to the circle are perpendicular to each other at the point of contact.

Given a line with slope m then the slope of a line perpendicular to it is

= - = - = - 0.4

-0.4

Step-by-step explanation:

Given

Let r = radius

r = -2.5

The relationship between the slope of the tangent of the line and the radius is as follows;

Let ∆s represent slope

Mathematically, ∆s = -1/r

Substitute 2.5 for r

∆s = -1/2.5

∆s = -0.4

Hence, given that the radius of circle is 2.5, the slope of the line tangent to is -0.4

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step-by-step explanation: