Of the drivers who stop at a gas station, 91% purchase gasoline, and 5% purchase both gasoline and oil. a total of 9% purchase oil. (a) what is the probability that a driver purchases oil, given that he or she purchases gasoline? round your answer to 2 decimal places. (b) what is the probability that a driver purchases gasoline, given that he or she purchases oil? round your answer to 2 decimal places.

a) 0.05

b) 0.56

Step-by-step explanation:

Let A be denote the event that gas station purchase gasoline.

B be denote the event that gas station purchase oil.

As per given description, we have

P(A)-0.91   , P(B)= 0.09  ,    P(A ∩B)=0.05

Then, the probability that a driver purchases oil, given that he or she purchases gasoline will be :-

 [Conditional probability formula.]

Similarly , The probability that a driver purchases gasoline, given that he or she purchases oil will be :-

3< x< 5

step-by-step explanation:

|x - 4| < 1

there are two solutions, one positive and one negative.   remember to flip the inequality when taking the negative solution

x-4 < 1       x-4 > -1

add 4 to each side

x-4+4 < 1+4       x-4+4 > -1+4

x< 5                 x> 3

3< x< 5

answer: .64

step-by-step explanation

set up the formula for standard deviation for this set of numbers, then simplify