Jonathon and samantha row their canoe 26 miles downstream in 2 hours. after a picnic, they row back upstream. after 3 hours they only travel 15 miles. assuming that they canoe at a constant rate and the river's current is constant, find the speed at which jonathon and samantha can row in still water.

9 mph

Step-by-step explanation:

Given

During downstream it took 2 hr to cover 26 miles

During upstream it took 3 hr to cover 15 miles

Let v be the canoe velocity and be the stream velocity

thus

------1

and

--------2

From 1 & 2 we get

2v=18

v=9 mph

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."