The width of a rectangle is 19 meters more than the length. the perimeter is 242 meters. find the length and width.

The length of the rectangle is 51 meters and the width is 70 meters.

Step-by-step explanation:

Let us assume that the length of the rectangle is L and the width of the same rectangle is W.

it is given in the problem that, the width of the rectangle is 19 meters more than the length.

Hence, L+19 =W (1)

Again, the perimeter of the rectangle is given by 2(L+W), which is given to be 242 meters.

So, 2(L+W) =242, ⇒L+W =121 (2)

Now, solving equations (1) and (2) by substitution method, we get,

L+(L+19) =121, ⇒2L =102, ⇒ L =51 meters.

Now, from equation (1), W=L+19 =70 meters.

Therefore, the length of the rectangle is 51 meters and the width is 70 meters. (Answer)

24/56=hx^7

step-by-step explanation: