The width of a casing for a door is normally distributed with amean of 24 inches and a standard deviation of 1/8 inch. the widthof a door is normally distributed with a mean of 23 and 7/8 inchesand a standard deviation of 1/16 inch. assume independence.

a) determine the mean and standard deviation of the differencebetween the width of the casing and the width of the door.

b) what is the probability that the width of the casing minus thewidth of the door exceeds 1/4 inch?

c) what is the probability that the door does not fit in thecasing?

answer: the answer to your question is parallel

first, we define the variables:

x: number of years after 1950

f (x): amount of vinyl sold.

then, with the variables defined, we have:

68594 vinyl records were sold in 1958 > f (8) = 68594

91299 vinyl records were sold in 1961 > f (11) = 91299

38720 vinyl records were sold in 1952 > f (2) = 38720

161743 vinyl records were sold in 1967 > f (17) = 161743

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step-by-step explanation:

22.83 repeating

step-by-step explanation:

137 ÷ 6 is 22.8333333 therefore we understand that 3 is repeating.

happy to

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could you provide figure.